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- SOLVED: For a gas at a given temperature, the compression factor is described by the empirical equation: z = 1 - 8.50 × 10^(-3)P/P° + 3.50 × 10^(-5)(P/P°)^2 where P° = 1
SOLVED: For a gas at a given temperature, the compression factor is described by the empirical equation: z = 1 - 8.50 × 10^(-3)P/P° + 3.50 × 10^(-5)(P/P°)^2 where P° = 1
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VIDEO ANSWER: Hello students: let's look at the question: l n, that integrate integration and 0 z minus 1 bracket, close d p by p here. Minus 1 is equal to minus 8.50 into 10 to the power minus 3 p by p, not plus 3.50 into 10. To the power minus 9. P
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SOLVED: Plot bclon shcs now compressibility factor (Ziofa non-Idc? 935 relative to an ideal gas; J1 force differential Mocraiurc: Values of Z indicate compressibility and inan re any more compressible ideal gas
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